Y=4x^2+28+24

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Solution for Y=4x^2+28+24 equation: 



=4Y^2+28+24

We move all terms to the left:

-(4Y^2+28+24)=0

We get rid of parentheses

-4Y^2-28-24=0

We add all the numbers together, and all the variables

-4Y^2-52=0

a = -4; b = 0; c = -52;
Δ = b2-4ac
Δ = 02-4·(-4)·(-52)
Δ = -832
Delta is less than zero, so there is no solution for the equation

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